coach d wrote:
The odds are 50%, but not because of what you said. Assuming Renato meant a 20% chance to EACH of Solomon and Symmonds--
odds of Aman losing: 1 - 0.35 = 0.65
odds of Souleyman losing: 0.8
odds of an unknown losing: 0.9
Odds of a non-American (that's Aman AND Souleyman AND an unknnown) NOT winning: 0.65 * 0.8 * 0.9 = 0.468
Chances of Solomon or Symmonds winning = 1 - .468 ~ 53.2%
You guys all spent too many days doing mileage when you should have been in class.
Put the same problem another way:
Given four overturned aces what are the chances of picking the ace of spades? The answer is 25%. The chance of not picking the ace of spades is (1-.25) or 75%. It is not the product of the complementary independent probabilities as you suggest. You’re saying it’s 31.64% , or (1-.25)*4.
You're welcome to my poker table any day.
"In no other branch of mathematics is it so easy for experts to blunder as in probability theory" - Martin Gardner