ok need some help from the math whizzes out there
sec x - 1 / 1- cos x = sec x
and
(1 + sin x /cos x) + (cos x / 1 + sin x) = 2sec x
any help would be greatly appreciated, i am stumped.
ok need some help from the math whizzes out there
sec x - 1 / 1- cos x = sec x
and
(1 + sin x /cos x) + (cos x / 1 + sin x) = 2sec x
any help would be greatly appreciated, i am stumped.
you need to do a better job of grouping the parts of your problem together so it can be understood correctly
I think this is a boolean group.
sorry,
(sec x - 1) / (1- cos x) = sec x
and
(1 + sin x /cos x) + (cos x / 1 + sin x) = 2sec x
uhhhhhh are you serious???
i almost feel like an idiot for responding but..
for part 1: multiply both sides by (1-cosX), which gives you sec x - 1 = sec x - 1.
for part two: put the left side into one fraction (1 + 2 sin X + sin^2 x + cos^2 x) / (cosX(1 + sinX))
= (2(1 + sinX))/((cosX*(1+sin X))
= 2/cos(x)
= 2 sec(x)
now...run along and finish the rest of your 7th grade hw
for the first one all you need to do is replace cos x with sec x and the rest is easy simplification so you have:
(secx-1)/(1-(1/secx)) = sec xand then
(secx - 1)/((secx-1)(secx) = sec x
(secx)(secx - 1)/(secx - 1) = sec x
secx = secx
1/sec x, sorry for the typo
What the f*** is that shit? You guys talking in some kind of secret code language or something?
thanks
and its 11th grade haha, i feel like i have the math ability of a 7th grader
Dude, if you can't even do those simple proofs, you are gonna fail that class. Damn you are stupid.
I didn't do those trig identities until last year at school or 1st year uni.
Give him a break
Yeah, I didn't do them until tenth grade, last year.
Actually Mr. "aa is for quitters" you may not multiply both sides of the identity by (1-cos x). That's not allowed when proving identities. Technically, you may only work on one side of the identity in order to prove the other side. So, you should start by multiplying the left side by (1+cos x)/(1+cos x)...then do some algebra ...then change everything to sin or cos and it will fall into place.