If I am a fool then I cannot solve:
cscX+cotanX=1
I cannot solve it, thus I am a fool
Please greater Letsrun community
Help a fool
If I am a fool then I cannot solve:
cscX+cotanX=1
I cannot solve it, thus I am a fool
Please greater Letsrun community
Help a fool
Write it in terms of sine and cosine.
First, write cscX and cotX in terms of sinX and cosX:
cscX + cotX = 1
1/sinX + cosX/sinX = 1
Next, multiply both sides by sinX (this will eliminate the fractions):
1 + cosX = sinX
Next, subtract cosX from both sides:
1 = sinX - cosX
Next, square both sides:
1 = sin^2(X) - 2sinXcosX + cos^2(X)
Rearrange the terms:
1 = sin^2(X) + cos^2(X) - 2sinXcosX
Recall the trig identity that sin^2 + cos^2 = 1, so let's replace sin^2(X) + cos^2(X) with 1:
1 = 1 - 2sinXcosX
Subtract 1 from both sides:
0 = -2sinXcosX
Divide both sides by -2:
0 = sinXcosX
This means one of two cases. Either,
sinX = 0 or cosX = 0
Solve each:
X = 0 or X = 90 degrees
When you plug in X = 0 into the original question, you find an error (dividing by 0)...therefore, the answer is:
X = 90 degrees.
Sorry if that explanation was excessive...hope it helps.
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