I think this is a great idea! I will be joining. The snow might make it tough for me here though.
Onceinalifetime wrote:
Tomorrow is 1-11-11. Ran a marathon on 10-10-10. Need something special to do. Maybe I'll run as far as I can in 1:11:11. Join me?
Just calculated the incline you'd have to set your treadmill to to do this and if I've done my math correctly it's an.... 11% incline.
planB. wrote:
needs to be 11.1 miles, with a 11,111' climb in 1:11:11 on 1-11-11
As much as I want to believe you, my calculations say ~19%...
Kyp Lyttyn wrote:
Just calculated the incline you'd have to set your treadmill to to do this and if I've done my math correctly it's an.... 11% incline.
Tell me where I'm going wrong...
duckshirt wrote:Kyp Lyttyn wrote:As much as I want to believe you, my calculations say ~19%...
Just calculated the incline you'd have to set your treadmill to to do this and if I've done my math correctly it's an.... 11% incline.
Well screw me raw. All these years I've been using a treadmill and had assumed that a 5% incline meant that I was climbing up a 5 degree angle. That does make the math much easier to calculate the elevation gain on a treadmill, but I now have to modify my original statment:
The Stache wrote:
You figured out the same thing here:
"vertical side / hypotenuse = 0.19304931025353339227 "
I modified your equation slightly to show you calculated a 19% incline. Keep in mind that percent incline and degrees of an angle are different. Percent incline is distance of rise/distance of horizontal travel. So, a 19% incline has you rise 19 feet for every 100 feet of horizontal travel.
Actual overground distance traveled would then be sqrt(100^2 + 19^2)=101.8 feet. You are running the distance of the hypotenuse if you will.