very interesting question
takes lot of working out
for most accurate wind resistance estimate, use jrm's calculator :
http://myweb.lmu.edu/jmureika/track/wind/index.html
we have 4'00 pace ( 14.91s for 100m ) on a treadmill without the wind resistance outdoors
we need to add wind speed of -( 1609.344/240 ) to this for outdoor equivalent = 15.33 s for 100m or 4'06.7 pace for mile outdoors ( 6.52m/s constant speed )
to work out how far he can go, we need :
http://www.jundo.co.uk/
& enter his best 5k/10k at his peak with adjustment for wabbiting
he was probably 12'35/26'10 at his peak with perfect pace
now, wabbiting offers ~ 1s/lap advantage & normally it is to 3k in a 5k ( 7.5s help ) & 1/2 way in a 10k ( 12.5s help )
therefore he was likely in solo shape of
12'42.5/26'22.5 at his peak
enter those into the predictor & by trial'n'error find the distance which offers 6.52m/s ( see above ) ->
5550m in 14'11
ust over 14 minutes at 4'00 pace on the treadmill !