malmo wrote:
I'll repeat. Determining the probability of event B happening today is not the product of the complementary probabilities of two or more events that have happened in the past.
kartelite wrote:
I get what you're saying, which is a pretty fundamental point, but I don't think that anyone is really assuming those are actual probabilities of some event.
That's exactly what the Brojos are saying.
kartelite wrote:
It assumes homogeneity among runners, that the probability of "success" (sub-2:07) is the same for this race and in prior ones (the "sample"), i.e. you're making iid Bernoulli draws. Under these unrealistic assumptions, 71% may be the MLE of "success" for each runner at Boston, and then you could estimate the probability of 0 successes at 0.29^8 or whatever.
But that's not what the Brojos are saying. They've taken the success rates of each of nine runners and aggregated them, then applied a metric to them that would only be used for calculating the probability of the undesired outcome (complementary result) of a series of nine independent events. Boston marathon is a single event and the probable outcomes are incalculable.
Forget the arbitrary assignment of the 2:07 number and follow me here.
The logic of their “calculations” is that since the aggregate success ratio of sub2:07 marathons is 22/31 or 71% the failure ratio must be the complement of that number, or 29%. Now they go one step further, without ANY mathematical reasoning at all, and decide that the chance of NO ONE running is the product of this complementary number (0.29) multiplied by the number of athletes that make up this pool. That makes no sense at all, because Kimetto, Desis and Regassa are perfect as far as sub-2:07 marathons. So the three of them are part of that aggregate pool that gives a total of 29% 2:07 misses. There is no dependent relationship between their perfect 2:07 performance ratios (100%) and the other 6 runners that make up the group of nine.
What the Brojos are trying to do (without a math basis) is calculate the number of times that the group as a whole would not break 2:07 in 9 consecutive trials, as if the results of an athletic event is the result of the product of random independent probabilities. Once again, this is wrong..
Following their looped logic, after the first trial there is a 29% failure rate. No accounting for the perfect records of Kimetto, Desis and Regassa.
After the 2nd trial 0.29x0.29 = 0.0841 No accounting for the perfect records of Kimetto, Desis and Regassa. Al three would have run 2:07 or better
After the 3rd trial 0.29 x .029 x 0.29 = 0.02438 No accounting for the perfect records of Kimetto, Desis and Regassa
All the way down to the ninth trial 0.29^9 = 0.0051% No accounting for the perfect records of Kimetto, Desis and Regassa, and once again no mathematical rational for making calculations in that way.
SISO.