If a snail is at the bottom of a 10=foot hole, it is able to crawl up 3 feet each day but falls back 2 feet at the end of the day. At that rate, how long will it take the snail to crawl out of the whole?
If a snail is at the bottom of a 10=foot hole, it is able to crawl up 3 feet each day but falls back 2 feet at the end of the day. At that rate, how long will it take the snail to crawl out of the whole?
3 feet - 2 feet = 1 foot. Given 10=foot hole, it follows foot = 10/hole, so 1 foot = 1 10/hole. Also whole = w10/foot. Thus, crawling out of the whole takes w10 hole.
9. He gets awfully close on the 8th before falling two feet, poor little guy.
Nope
This one may be right. The snail hits a maximum height of 10 feet on day 8. 10 feet gets the snail to the rim of the hole, not out of the hole. Day 9 gets the snail completely out.
Idk bro. Obviously he peaks at 10 feet off the ground on the 8th day but hoe can you expect him to turn the corner? If the front of his body is ten feet up and then he falls, he won’t actually make it OUT of the hole until the 9th day.
A snail is at one end of an 1m long, infinitely elastic rubber band. The snail moves at a non-stop pace of 1cm/min, while the rubber band stretches at a non-stop pace of 1m/min. Will the snail reach end of the band?