hello, Ventolin, you babbling imbecile.
This is a power problem, not a drag problem.
simple empirical Runner's World formula: 2 seconds/pound/mile is more accurate than your gibberish.
for, "a 60kg guy wearing a smooth-fitting, unimpeding 1kg belt around his waist runs a M in 2"05'00.00 what could he have run for it without the belt ???"
2"03'04.7
In addition to using a ridiculous formula, you are so dumb you cannot even do simple math or proofread your formulas:
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100g less -> (59.9/60.0)^3 * 125'00.00 = 2"04'55.83
200g less -> (59.8/60.0)^3 * 125'00.00 = 2"04'51.65
125'00.00 * ( 59/60 )^3 = 2"04'18.1
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Good job cursing out the math prof who actually used your formula and got the correct values. Hint: your formulas work with ^(1/3), but there is still no way in this physical world that you can justify either ^3 or ^(1/3).
Before forcing me to read your drivel again, please consult with a high school freshman who understands algebra and basic physics.