Aerodynamicist wrote:
If someone got lapped on a velodrome, do you think they would be able to come back and still win a 26 mile ride in under an hour.
And another thing, the drag equation for airplanes or cars or anything else in creation is
Drag=Viscosity*Velocity^2*Drag Coefficient*Area
Or perhaps you meant that a cyclist's douchebaggery coefficient tends to raise the velocity to a cubic?
ThunderThighs wrote:A velodrome ride is not the same as a road ride. You don't get high g-forces out on the road. And aerodynamic drag is cubic. It takes exponentially more energy to ride at 33 mph then at 26 mph, something that runners don't understand.
Spoken like a basement dwelling millennial who has trouble passing physics class in highschool. Your statement about the velodrome doesn't even make sense in regards to the situation here, I don't think you even know what a velodrome is.
And you don't even know the proper power equation when cyclists refer to cubic losses:
Putting it all together, the equation that relates the power produced by your legs to the steady-state speed you travel is:
Plegs (watts) = (1-(Lossdt/100))-1 · (Fgravity + Frolling + Fdrag) · V (m/s)
or, more fully:
Plegs (watts) = (1-(Lossdt/100))-1 · ( ( 9.8067 (m/s2) · W (kg) · ( sin(arctan(G/100)) + Crr · cos(arctan(G/100)) ) ) + ( 0.5 · Cd · A (m2) · Rho (kg/m3) · (V (m/s))2 ) ) · V (m/s)
One of the scary implications of this equation is that at high speed, the power you have to produce is proportional to the cube of your velocity. So, to increase your speed by 25%, you need to nearly double your wattage!
Go back to your basement.
