why am i so dumb wrote:
Here is a picture to illustrate the point I am stuck on:
http://www.aww-kittah-aww.com/up/public/191992/math.jpg
Forgive me if this has been posted.
1) Use the graph you have.
2) The right triangle formed between the origin, (12,0) and the point on the circle you are seeking has a hypotenuse of length 12 and a leg of length 8 due to the circle. The line from (12,0) to the point in question has a length of 80^0.5.
3) Use the line with the length of 80^0.5 as the hypotenuse of a right triangle with one of the legs dropping from the point in question perpendicular to the x axis.
4) Solve the right triangle equation for the triangle in step 3. 80=(12-x)^2+y^2.
5) Substitute y^2=64-x^2 into the eqn. in step 4 since you know the point must lie on the circle and you can find y and then x.
6) Double check that the resulting (x,y) coordinate is correct. Find the angles that 2 lines form with the x axis, one line from the origin through the solved x,y point and one line from (12, 0) through the solved x,y point. If these 2 angles don't add to 90 degrees, try again.