notafan wrote:
Can someone explain to me, with this description, how you wouldn’t be guaranteed to win if you bought all 1,000 numbers? That was my impression under the OPs first post and has only been fortified now.. but I’ll admit I’m not the sharpest tool in the shed.
I see the confusion here. Let me explain, there is only one number for which if you roll it, you get a billion dollars, for example 69. For every 1,000 you pay, you get another ROLL, not another number. So you would be correct that if you bought 1,000 numbers, you’d win it 100%, but in this scenario you just get another roll.
Also, I’ve seen some questionable math on here so let me set the record, if you buy 1,000 tickets, you have a 63% chance of getting at least one ticket that hits the jackpot. It’s hard to logically understand how it isn’t 50% so I’ll explain it in English, and then show the math. Basically it would be 50% if “winning” only included hitting the jackpot once. By the 1000th roll, the probability is 50% that you have hit it exactly once already. But we also can include hitting it multiple times in the definition of winning . So the probabilities of hitting in twice, and three times, and four times etc all add up to another 13 percent chance, giving us the probability of winning 63%.
The math is calculated like this, what’s the probability of missing the win on every roll? Once you find that, then the opposite of that probability is the probability of anything besides losing every time, ie winning.
So the probability of losing a 1/1000 chance is 999/1000. The chances of losing 1,000 times in a row is (999/1000)^1,000 which is roughly 0.36. 36% chance of losing 1,000 rolls means a 63% chance of doing anything but losing, ie winning, but also winning multiple times.
Also, someone asked about 50% and 75% and 90% but I’m too lazy and it’s considerably easier to calculate going the other way around, so hopefully these are useful -
1million = 1000 tickets = 63% of winning
2 mil = 2000 tickets = 86.5%
5 mil = 5000 tickets = 99.4%