I have some lines in a file that look like this:
0 3 0
0 5 0
1 0 1
I want to store it in a list, like [0 3 0 0 5 0 1 0 1]
Currently I have:
for i in range(0, 3):
-> mytmp = lines.split()
-> for j in range(0, 3):
-> -> myList.append(float(mytmp[j])
Is there a way to condense this to one line? I know myList = [next(filename) for i in range(0, 3)] will do the beginning part of the code, but is there a way to split things as well and then store those elements all in one line? Thanks!
I don't know if you can, but why do you want to? Is it just for fun? If this is a homework assignment or something, then don't condense it. It makes the code unreadable. Bad practice.
Mostly just for fun, and to make things more pythonic.
dgfdgdgdgdgd wrote:
I have some lines in a file that look like this:
0 3 0
0 5 0
1 0 1
I want to store it in a list, like [0 3 0 0 5 0 1 0 1]
Currently I have:
for i in range(0, 3):
-> mytmp = lines.split()
-> for j in range(0, 3):
-> -> myList.append(float(mytmp[j])
Is there a way to condense this to one line? I know myList = [next(filename) for i in range(0, 3)] will do the beginning part of the code, but is there a way to split things as well and then store those elements all in one line? Thanks!
Of course there is! It’s Python elwe are talking about after all.
You can condense all in one line by using numpy.reshape (look up the documentation of the numpy package).
What you wrote above is very very manual. Instead just import your data as a matrix or np array (look up the pandas package) and then manipulating becomes very easy.
yes:
myList = [num for row in lines for num in row]
This is sometimes confusing as a list comprehension, but you can think of this as:
for row in lines:
for num in row:
myList.append(num)
If there's just the three lines in the file . . .
with open("myFile.txt") as indata: a = [int(x) for x in indata.read().split()]
import io
from itertools import chain
with io.open('/path/to/file', 'r') as f:
L = [int(x) for x in chain(*[line.split() for line in f])]
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