Reaction of: Potassium phosphate and Cobalt (II) nitrate
Balanced chem equation... so first of all it is:
K3PO4 + Co(NO3)2 -> KNO3 + Co3(PO4)2
I can figure out the ions etc. later but how do you balance this? If you try to add a 3 in front of some of them to get the K to 3 and the Co to 3, it throws off the N and the O..
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2K3PO4 + 3Co(NO3)2 = 6KNO3 + Co3(PO4)2
(2)K3PO4 + (3)Co(NO3)2 --> (6)KNO3 + Co3(PO4)2
if i remember my rules correctly that should work.
Isn't it 5 N on the left and 6 on the right? Or do you take 3 N *2 = 6 N?
Also...
Is there a reaction for these reactants... why or why not?:
Na2CO3 and LiNO3
And
HI(aq) + Zn(NO3) 2(aq)
Thanks
erghhhh wrote:
Isn't it 5 N on the left and 6 on the right? Or do you take 3 N *2 = 6 N?
this.
Oh nevermind I got it it's because everything would dissociate/no precipitate would form for these.
erghhhh wrote:
Is there a reaction for these reactants... why or why not?:
Na2CO3 and LiNO3
And
HI(aq) + Zn(NO3) 2(aq)
Thanks
Na2CO3 + (2)LiNO3 --> (2)NaNO3 + Li2CO3
if you separate this into the net ionic equation, NaNO3 is soluble, so therefore there is a reaction and Li2CO3 is the precipitate because carbonates are usually not soluble in aqueous solution.
(2)HI + Zn(NO3)2 --> (2)HNO3 + ZnI2
i'm not sure...but i've never seen this before, so i would guess no reaction...i really don't know though.
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