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| bumblebee |
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this may be easy, but my brain just doesn't work this way. A bicycle wheel has a diameter of 63.4 cm and a mass of 1.78 kg. Assume that the wheel is a hoop with all of the mass concentrated on the outside radius. The bicycle is placed on a stationary stand and a resistive force of 117 N is applied tangent to the rim of the tire. What force must be applied by a chain passing over a 9.09 cm diameter sprocket if the wheel is to attain an acceleration of 4.56 rad/s2? |
| bumblebee |
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a little bit |
| irun |
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work it backwards |
| bumblebee |
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I would love to, but I have no idea what the hell I am doing. if you could even give me a formula I would be happy |
| dsfjdsgf |
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Diameter, mass, geometry of wheel give you moment of inertia. You have two forces applied with different radius from the center, so different torques. You want to achieve a certain acceleration, which can only be done if there's a difference in torques. Finally, Torque = (Moment of inertia) x (angular acceleration) |
| bumblebee |
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thank you for that |
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