phstenning wrote:
keystone light knight wrote:again, what is this force holding the plane above the treadmill that allows it to be unaffected by the motion of the belt?
The thrust of the propellor/jet acting on the plane, obviously.
you do realize that the thrust of the engines only acts in a horizontal direction, right? unless we are talking about thrust-vectoring or VTOL aircraft, then there is not net upward force until it has reached takeoff speed.
there is a definite interpretation problem with the original question since i think it was poorly asked. let's get some things straight. the question clearly defines the initial situation as a stationary plane sitting on a motionless treadmill. now, from a dead stop, the plane's engines switch on and the treadmill belt begins to move at the same moment. this is where the riddle gets cloudy. talking about simply the "speed" of the airplane compared to the treadmill is too ambiguous, but maybe that's why it is considered a riddle. the question should have been more specific - does it mean the acceleration of the wheels? clearly, there is some sort of idea of equal forces going on here. i suppose if we take it 100% literally, and the speed of the airplane (relative to a stationary observer) is the same as the speed of the treadmill (belt going backward), then it simply means the airplane is applying twice as much thrust as it would normally apply to reach take-off speed, in order to counter the backward motion of the treadmill and accelerate beyond that point of equilibrium. that is a pretty stupid question and perhaps that is why it is posed as a riddle and not a physics question, but i suppose in that case then yes, obviously the plane will fly - but this frictionless/free-spinning wheels/engines hold the plane off the runway idea is false and not the reason. it would simply be a trick question and thus the treadmill is just a red herring.
but, if you take "speed of the airplane" to mean "force that would normally be required to achieve the same speed on a standard runway," then no, the plane will not fly, for reasons that i have stated.